![]() Q7. Determine current through each diode in the circuit shown in Fig. 6 (ii).īy symmetry, current in each branch is I D so that current in branch CD is 2I D.Īpplying Kirchhoff’s voltage law to the closed circuit ABCDA, we have, The resulting circuit will be as shown in Fig. Replace the diodes by their simplified models. Find V Q and I D in the network shown in Fig. The silicon diode never gets the opportunity to have 0.7 V across it and, therefore, remains in open-circuit state as shown in Fig.5(ii). When voltage is applied, germanium diode (V0 = 0.3 V) will turn on first and a level of 0.3V is maintained across the parallel circuit. It appears that when the applied voltage is switched on, both the diodes will turn “on”. Q5. Find the voltage V A in the circuit shown in Fig. 4 (ii).įurther, diode D1 can be replaced by its simplified equivalent circuit. We can, therefore, consider the branch containing diode D2 as open as shown in Fig. The conditions of the problem suggest that diode D1 is forward biased and diode D2 is reverse biased. Assume the diodes toīe of silicon and forward resistance of diodes to be zero. Q4. Determine the current I in the circuit shown in Fig. As we know for a silicon diode, the barrier voltage is 0.7 V. Replacing diodes D1 and D3 by their equivalent circuits and making the branches containing diodes D2 and D4 open, we get the circuit shown in Fig. We can, therefore, consider the branches containing diodes D2 and D4 as “open”. 3 (i).Īssume the diodes to be of silicon and forward resistance of each diode is 1 Ω.ĭiodes D1 and D3 are forward biased while diodes D2 and D4 are reverse biased. Q3. Calculate the current through 48 Ω resistor in the circuit shown in Fig. Since the diode is ideal, it has zero resistance 2 (ii) shows Thevenin’s equivalent circuit. ![]()
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